1958 Iowa gubernatorial election explained

Election Name:1958 Iowa gubernatorial election
Country:Iowa
Flag Image:Flag of Iowa (variant).svg
Type:Presidential
Ongoing:no
Previous Election:1956 Iowa gubernatorial election
Previous Year:1956
Next Election:1960 Iowa gubernatorial election
Next Year:1960
Election Date:November 4, 1958
Image1:File:Herschel C. Loveless (cropped).jpg
Nominee1:Herschel C. Loveless
Party1:Democratic Party (United States)
Popular Vote1:465,024
Percentage1:54.13%
Nominee2:William G. Murray
Party2:Republican Party (United States)
Popular Vote2:394,071
Percentage2:45.87%
Map Size:240px
Governor
Before Election:Herschel C. Loveless
Before Party:Democratic Party (United States)
After Election:Herschel C. Loveless
After Party:Democratic Party (United States)

The 1958 Iowa gubernatorial election was held on November 4, 1958. Incumbent Democrat Herschel C. Loveless defeated Republican nominee William G. Murray with 54.13% of the vote.

Primary elections

Primary elections were held on June 2, 1958.[1]

Democratic primary

Candidates

Results

Republican primary

Candidates

Results

General election

Candidates

Results

Notes and References

  1. Web site: Summary of Official Canvass of Votes Cast in Iowa Primary Election . . 1958 . March 27, 2020.