1957 French Championships – Women's singles explained

First-seeded Shirley Bloomer defeated Dorothy Knode 6–1, 6–3 in the final to win the women's singles tennis title at the 1957 French Championships.^[1]

Seeds

The seeded players are listed below. Shirley Bloomer is the champion; others show the round in which they were eliminated.

1. Shirley Bloomer (champion)
2. Dorothy Knode (finalist)
3. Christiane Mercelis (quarterfinals)
4. Edda Buding (third round)
5. Darlene Hard (quarterfinals)
6. Mary Hawton (third round)
7. Silvana Lazzarino (second round)
8. Annalissa Bellani (third round)
9. Zsuzsi Körmöczy (quarterfinals)
10. Heather Brewer (quarterfinals)
11. Jacqueline Kermina (second round)
12. Ginette Bucaille (second round)
13. Vera Puzejova (semifinals)
14. Erika Vollmer (third round)
15. Pilar Barril (third round)
16. Yola Ramírez (third round)

Draw

Key

• Q = Qualifier
• WC = Wild card
• LL = Lucky loser
• r = Retired

Earlier rounds

Section 4

External links

• Web site: Official 1957 Women's Draw . 2007-04-29 . https://web.archive.org/web/20070930211017/http://www.fft.fr/rolandgarros/pdfpalmares/femmes1957_en.pdf . 2007-09-30 . dead .   on the French Open website

Notes and References

1. Book: Collins, Bud. The Bud Collins History of Tennis. 2010. New Chapter Press. [New York]. 978-0942257700. 2nd. 395.