1956 United States Senate election in Iowa explained

Election Name:	1956 United States Senate election in Iowa
Country:	Iowa
Flag Image:	Flag of Iowa (xrmap collection).svg
Type:	presidential
Ongoing:	no
Previous Election:	1950 United States Senate election in Iowa
Previous Year:	1950
Next Election:	1962 United States Senate election in Iowa
Next Year:	1962
Election Date:	November 6, 1956
Image1:	File:Bourke B. Hickenlooper.jpg
Nominee1:	Bourke B. Hickenlooper
Party1:	Republican Party (United States)
Popular Vote1:	635,499
Percentage1:	53.92%
Nominee2:	Rudolph M. Evans
Party2:	Democratic Party (United States)
Popular Vote2:	543,156
Percentage2:	46.08%
Map Size:	240px
U.S. Senator
Before Election:	Bourke B. Hickenlooper
Before Party:	Republican Party (United States)
After Election:	Bourke B. Hickenlooper
After Party:	Republican Party (United States)

The 1956 United States Senate election in Iowa took place on November 6, 1956. Incumbent Republican Senator Bourke B. Hickenlooper was re-elected to a third term in office over Democrat Rudolph M. Evans.

General election

Candidates

• Rudolph M. Evans (Democratic), former member of the Federal Reserve Board of Governors^{[1] [2]}
• Bourke B. Hickenlooper, incumbent Senator since 1945 (Republican)

Results

See also

• 1956 United States Senate elections

Notes and References

1. News: . November 22, 1956 . R.M. EVANS DIES; ONCE FARM CHIEF; Ex-Administrator of A.A.A., Democrat, Was Defeated in Iowa Senate Race Nov. 6 Helped Write Farm Program . New York Times . New York City . 12 April 2022.
2. Web site: Rudolph M. Evans . . Federal Reserve History . 12 April 2022 .