1956 Iowa gubernatorial election explained

Election Name:1956 Iowa gubernatorial election
Country:Iowa
Flag Image:Flag of Iowa (variant).svg
Type:Presidential
Ongoing:no
Previous Election:1954 Iowa gubernatorial election
Previous Year:1954
Next Election:1958 Iowa gubernatorial election
Next Year:1958
Election Date:November 6, 1956
Image1:File:Herschel C. Loveless (cropped).jpg
Nominee1:Herschel C. Loveless
Party1:Democratic Party (United States)
Popular Vote1:616,852
Percentage1:51.22%
Nominee2:Leo Hoegh
Party2:Republican Party (United States)
Popular Vote2:587,383
Percentage2:48.78%
Map Size:240px
Governor
Before Election:Leo Hoegh
Before Party:Republican Party (United States)
After Election:Herschel C. Loveless
After Party:Democratic Party (United States)

The 1956 Iowa gubernatorial election was held on November 6, 1956. Democratic nominee Herschel C. Loveless defeated incumbent Republican Leo Hoegh with 51.22% of the vote.

Primary elections

Primary elections were held on June 4, 1956.[1]

Democratic primary

Candidates

Results

Republican primary

Candidates

Results

General election

Candidates

Results

Notes and References

  1. Web site: Summary of Official Canvass of Votes Cast in Iowa Primary Election . . 1956 . March 28, 2020.