1952 Iowa gubernatorial election explained

Election Name:1952 Iowa gubernatorial election
Country:Iowa
Flag Image:Flag of Iowa (variant).svg
Type:Presidential
Ongoing:no
Previous Election:1950 Iowa gubernatorial election
Previous Year:1950
Next Election:1954 Iowa gubernatorial election
Next Year:1954
Election Date:November 4, 1952
Image1:File:Bill Beardsley.png
Nominee1:William S. Beardsley
Party1:Republican Party (United States)
Popular Vote1:638,388
Percentage1:51.90%
Nominee2:Herschel C. Loveless
Party2:Democratic Party (United States)
Popular Vote2:587,671
Percentage2:47.78%
Map Size:240px
Governor
Before Election:William S. Beardsley
Before Party:Republican Party (United States)
After Election:William S. Beardsley
After Party:Republican Party (United States)

The 1952 Iowa gubernatorial election was held on November 4, 1952. Incumbent Republican William S. Beardsley defeated Democratic nominee Herschel C. Loveless with 51.90% of the vote.

Primary elections

Primary elections were held on June 2, 1952.[1]

Democratic primary

Candidates

Results

Republican primary

Candidates

Results

General election

Candidates

Major party candidates

Other candidates

Results

Notes and References

  1. Web site: Summary of Official Canvass of Votes Cast in Iowa Primary Election . . 1952 . April 3, 2020.