1950 Iowa gubernatorial election explained

Election Name:1950 Iowa gubernatorial election
Country:Iowa
Flag Image:Flag of Iowa (variant).svg
Type:Presidential
Ongoing:no
Previous Election:1948 Iowa gubernatorial election
Previous Year:1948
Next Election:1952 Iowa gubernatorial election
Next Year:1952
Election Date:November 7, 1950
Nominee1:William S. Beardsley
Party1:Republican Party (United States)
Popular Vote1:506,642
Percentage1:59.10%
Nominee2:Lester S. Gillette
Party2:Democratic Party (United States)
Popular Vote2:347,176
Percentage2:40.50%
Map Size:240px
Governor
Before Election:William S. Beardsley
Before Party:Republican Party (United States)
After Election:William S. Beardsley
After Party:Republican Party (United States)

The 1950 Iowa gubernatorial election was held on November 7, 1950. Incumbent Republican William S. Beardsley defeated Democratic nominee Lester S. Gillette with 59.10% of the vote.

Primary elections

Primary elections were held on June 5, 1950.[1]

Democratic primary

Candidates

Results

Republican primary

Candidates

Results

General election

Candidates

Major party candidates

Other candidates

Results

Notes and References

  1. Web site: Summary of Official Canvass of Votes Cast in Iowa Primary Election . . 1950 . April 8, 2020.