1949 Tour de Hongrie explained

1949 Tour de Hongrie
Date:29 June – 3 July
Stages:5
Distance:1036[1]
Unit:km
Time:31h 23' 33"
First:André Labeylie
First Nat:FRA
Second:Rudolf Lauscha
Second Nat:AUT
Third:Roger Bourgeteau
Third Nat:FRA
Team:France (national team)
Previous:1943
Next:1953

The 1949 Tour de Hongrie was the 14th edition of the Tour de Hongrie cycle race and was held from 29 June to 3 July 1949. The race started and finished in Budapest. The race was won by André Labeylie.

Route

Stages of the 1949 Tour de Hongrie
StageDateRouteDistanceWinner
129 JuneBudapest to Debrecen229km (142miles)
230 JuneDebrecen to Miskolc231km (144miles)
31 JulyMiskolc to Budapest184km (114miles)
42 JulyBudapest to Keszthely192km (119miles)
53 JulyKeszthely to Budapest200km (100miles)
Total1036km (644miles)

General classification

Final general classification[2]
RankRiderTeamTime
1France
2Austria+ 10' 01"
3France+ 15' 02"

Notes and References

  1. Web site: 14. Tour de Hongrie: Francia uralom (1949). tdh.hu. 15 July 2019.
  2. Web site: 1949 Tour de Hongrie. First Cycling. 15 July 2019.