1949 Tour de Hongrie explained
1949 Tour de Hongrie |
Date: | 29 June – 3 July |
Stages: | 5 |
Distance: | 1036[1] |
Unit: | km |
Time: | 31h 23' 33" |
First: | André Labeylie |
First Nat: | FRA |
Second: | Rudolf Lauscha |
Second Nat: | AUT |
Third: | Roger Bourgeteau |
Third Nat: | FRA |
Team: | France (national team) |
Previous: | 1943 |
Next: | 1953 |
The 1949 Tour de Hongrie was the 14th edition of the Tour de Hongrie cycle race and was held from 29 June to 3 July 1949. The race started and finished in Budapest. The race was won by André Labeylie.
Route
Stages of the 1949 Tour de HongrieStage | Date | Route | Distance | Winner |
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1 | 29 June | Budapest to Debrecen | 229km (142miles) | |
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2 | 30 June | Debrecen to Miskolc | 231km (144miles) | |
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3 | 1 July | Miskolc to Budapest | 184km (114miles) | |
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4 | 2 July | Budapest to Keszthely | 192km (119miles) | |
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5 | 3 July | Keszthely to Budapest | 200km (100miles) | |
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Total | 1036km (644miles) | |
General classification
Final general classification[2] | |
Notes and References
- Web site: 14. Tour de Hongrie: Francia uralom (1949). tdh.hu. 15 July 2019.
- Web site: 1949 Tour de Hongrie. First Cycling. 15 July 2019.