1947 U.S. National Championships – Women's singles explained

Second-seeded Louise Brough defeated first-seeded Margaret Osborne 8–6, 4–6, 6–1 in the final to win the women's singles tennis title at the 1947 U.S. National Championships.^{[1] [2]}

Seeds

The tournament used two lists of players for seeding the women's singles event; one for U.S. players and one for foreign players. Louise Brough is the champion; others show in brackets the round in which they were eliminated.^{[3] [4] [5]}

1. Margaret Osborne (finalist)
2. Louise Brough (champion)
3. Doris Hart (semifinals)
4. Patricia Todd (quarterfinals)
5. Shirley Fry (third round)
6. Mary Arnold Prentiss (third round)
7. Dorothy Head (quarterfinals)
8. Barbara Krase (quarterfinals)
9. Nancye Bolton (semifinals)
10. Betty Hilton (third round)
11. Molly Blair (second round)
12. Magda Rurac (quarterfinals)
13. Nell Hopman (second round)
14. Joy Gannon (first round)
15. Jean Quertier (third round)
16. Elaine Fildes (first round)

Draw

Final eight

Notes and References

1. Book: Collins, Bud. The Bud Collins History of Tennis. 2010. New Chapter Press. [New York City]. 978-0942257700. 2nd. 470.
2. Book: The Lawn Tennis Almanack 1948. 1948. Ed. J. Burrow & Co. Ltd. G.P. Hughes. London. 148–151.
3. News: Seventeen Nations In U.S. Singles Tennis Tourney. Lewiston Evening Journal. AP. September 3, 1947. 13.
4. News: Gayle Talbot. National Singles Opens Today. St. Petersburg Times. AP. September 5, 1947.
5. News: Tom Brown and Geoff Brown Meet in Forest Hills Duel. The Day. Ap. September 11, 1947. 16.