Score: | 6–2, 6–4 |
Draw: | 96 |
Seeds: | 8 |
Before Year: | 1939 |
Type: | grand slam |
See main article: 1946 Wimbledon Championships.
Pauline Betz defeated Louise Brough in the final, 6–2, 6–4 to win the ladies' singles tennis title at the 1946 Wimbledon Championships.[1] Alice Marble was the defending champion, but was ineligible to compete after turning professional.
See also: 1 and 1. Pauline Betz (champion)
See also: 2 and 8. Margaret Osborne (semifinals)
See also: 3 and 6. Louise Brough (final)
See also: 4 and 3. Kay Menzies (quarterfinals)
See also: 5 and 4. Dorothy Bundy (semifinals)
See also: 6 and 5. Jean Bostock (quarterfinals)
See also: 7 and 7. Doris Hart (quarterfinals)
See also: 8 and 2. Simone Lafargue (fourth round)