1946 Wimbledon Championships – Women's singles explained

Score:6–2, 6–4
Draw:96
Seeds:8
Before Year:1939
Type:grand slam

See main article: 1946 Wimbledon Championships.

Pauline Betz defeated Louise Brough in the final, 6–2, 6–4 to win the ladies' singles tennis title at the 1946 Wimbledon Championships.[1] Alice Marble was the defending champion, but was ineligible to compete after turning professional.

Seeds

See also: 1 and 1. Pauline Betz (champion)

See also: 2 and 8. Margaret Osborne (semifinals)

See also: 3 and 6. Louise Brough (final)

See also: 4 and 3. Kay Menzies (quarterfinals)

See also: 5 and 4. Dorothy Bundy (semifinals)

See also: 6 and 5. Jean Bostock (quarterfinals)

See also: 7 and 7. Doris Hart (quarterfinals)

See also: 8 and 2. Simone Lafargue (fourth round)

Draw

Top half

Section 4

Bottom half

Section 8

Notes and References

  1. Book: Barrett, John. Wimbledon: The Official History. 2014. Vision Sports Publishing. 9-781909-534230. 4th.