1946 New Hampshire gubernatorial election explained

Election Name:1946 New Hampshire gubernatorial election
Country:New Hampshire
Type:Presidential
Ongoing:no
Previous Election:1944 New Hampshire gubernatorial election
Previous Year:1944
Next Election:1948 New Hampshire gubernatorial election
Next Year:1948
Election Date:November 5, 1946
Nominee1:Charles M. Dale
Party1:Republican Party (United States)
Popular Vote1:103,204
Percentage1:63.14%
Nominee2:F. Clyde Keefe
Party2:Democratic Party (United States)
Popular Vote2:60,247
Percentage2:36.86%
Map Size:245px
Governor
Before Election:Charles M. Dale
Before Party:Republican Party (United States)
After Election:Charles M. Dale
After Party:Republican Party (United States)

The 1946 New Hampshire gubernatorial election was held on November 5, 1946. Incumbent Republican Charles M. Dale defeated Democratic nominee F. Clyde Keefe with 63.14% of the vote.

Primary elections

Primary elections were held on August 6, 1946.[1]

Republican primary

Candidates

Results

General election

Candidates

Results

Notes and References

  1. Book: Guide to U.S. elections - CQ Press, Congressional Quarterly, inc . 2005 . CQ Press . 9781568029818 . 2020-06-01.