1946 Iowa gubernatorial election explained

Election Name:1946 Iowa gubernatorial election
Country:Iowa
Flag Image:Flag of Iowa (variant).svg
Type:Presidential
Ongoing:no
Previous Election:1944 Iowa gubernatorial election
Previous Year:1944
Next Election:1948 Iowa gubernatorial election
Next Year:1948
Election Date:November 5, 1946
Nominee1:Robert D. Blue
Party1:Republican Party (United States)
Popular Vote1:362,592
Percentage1:57.40%
Nominee2:Frank Miles
Party2:Democratic Party (United States)
Popular Vote2:266,190
Percentage2:42.14%
Map Size:240px
Governor
Before Election:Robert D. Blue
Before Party:Republican Party (United States)
After Election:Robert D. Blue
After Party:Republican Party (United States)

The 1946 Iowa gubernatorial election was held on November 5, 1946. Incumbent Republican Robert D. Blue defeated Democratic nominee Frank Miles with 57.40% of the vote.

Primary elections

Primary elections were held on June 3, 1946.[1]

Democratic primary

Candidates

Results

Republican primary

Candidates

Results

General election

Candidates

Major party candidates

Other candidates

Results

Notes and References

  1. Web site: Summary of Official Canvass of Votes Cast in Iowa Primary Election . . 1946 . April 12, 2020.