1944 Iowa gubernatorial election explained

Election Name:1944 Iowa gubernatorial election
Country:Iowa
Flag Image:Flag of Iowa (variant).svg
Type:Presidential
Ongoing:no
Previous Election:1942 Iowa gubernatorial election
Previous Year:1942
Next Election:1946 Iowa gubernatorial election
Next Year:1946
Election Date:November 7, 1944
Nominee1:Robert D. Blue
Party1:Republican Party (United States)
Popular Vote1:561,827
Percentage1:56.01%
Nominee2:Richard F. Mitchell
Party2:Democratic Party (United States)
Popular Vote2:437,684
Percentage2:43.63%
Map Size:230px
Governor
Before Election:Bourke B. Hickenlooper
Before Party:Republican Party (United States)
After Election:Robert D. Blue
After Party:Republican Party (United States)

The 1944 Iowa gubernatorial election was held on November 7, 1944. Republican nominee Robert D. Blue defeated Democratic nominee Richard F. Mitchell with 56.01% of the vote.

Primary elections

Primary elections were held on June 5, 1944.[1]

Democratic primary

Candidates

Results

Republican primary

Candidates

Results

General election

Candidates

Major party candidates

Other candidates

Results

Notes and References

  1. Web site: Summary of Official Canvass of Votes Cast in Iowa Primary Election . . 1944 . April 14, 2020.