1940 USSR Chess Championship explained

Event:12th Soviet Chess Championship (1940)
Location:Moscow
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The 1940 Soviet Chess Championship was the 12th edition of USSR Chess Championship. Held from 5 September to 3 October 1940 in Moscow. The tournament was won by Andor Lilienthal and Igor Bondarevsky. Twenty of the Soviet Union's strongest masters competed in the final, six of whom qualified in the semifinals in Kiev earlier that year: Eduard Gerstenfeld, Mark Stolberg, Igor Bondarevsky, Iosif Rudakovsky, Alexander Konstantinopolsky and Peter Dubinin. The remaining invitations went to the Soviet chess elite. Botvinnik did his worst championship, only drawing in 5th/6th position, losing matches to both winners. This championship marked the debut of Paul Keres (4th) and the future world champion Vassily Smyslov (3rd). USSR had expanded its territory in 1939-40, incorporating the Baltic states, which meant that the strong masters Paul Keres from Estonia and Vladimir Petrov from Latvia were able to participate. In 1941, the top six played a competition called Absolute Championship of Soviet Union, ending with Botvinnik's victory.[1]

Tables and results

Semifinal

Semifinal, Kiev, May 1940!!Player!1!2!3!4!5!6!7!8!9!10!11!12!13!14!15!16!17!Total
1 Eduard Gerstenfeld -½01½111½½1½½½1½½10½
2 Mark Stolberg ½-10½1101½111010110½
3 Igor Bondarevsky 10-11½½½½½1001½1110
4 Iosif Rudakovsky 010-1½1½1½½½1½½½½
5 Alexander Konstantinopolsky ½½00-1½1½1½½½1½½1
6 Peter Dubinin 00½½0-½01111½111½
700½0½½-½01111½111
801½½01½-0½1½½1½½19
9½0½0½011-00011111
10½½½½000½1-01½½½118
11000½½00011-1½10½17
12½01½½00½100-1½½½0
13½010½½0½0½½0-½½½½6
14½10½00½00½0½½-½1½6
1500½½½00½0½1½½½-016
16½10½½00½00½½½01-0
17½00½0½000001½½01-

Final

12th Soviet Chess Championship Final!!!1!2!3!4!5!6!7!8!9!10!11!12!13!14!15!16!17!18!19!20!Total
1 Andor Lilienthal -1½½½1111½½½½½1½½½1113½
2 Igor Bondarevsky 0-½1½1½11½011½½11½1113½
3½½-½½½0½111½½½111½1113
4½0½-½½010111½1½1111012
5½½½½-010½11½½½11011½11½
600½½1-0½11½½0111½1½111½
70½1101-0101½½½½½1½½½10½
800½01½1-0111½½½½101½10½
90001½001-1½½1½01½11110½
10½½0000100-½1½0½1111½9
11½1000½00½½-1½100½½11
12½0½0½½½0½00-11011½01
13½0½½½1½½0½½0-½10010½8
14½½½0½0½½½100½-10½½018
150½0½00½½1½1100-½0½1½8
16½00000½½001011½-1½1½8
17½0001½00½0½01½10-½017
18½½½000½100½½0½½½½-0½
1900000½½00001110011-½
200001½0½½0½00½0½½0½½-

1941 Absolute Champion of the USSR

The winner of the 1940 Soviet championship should face world champion Alexander Alekhine for the world title. Nor did the result settle the question of which Soviet playershould challenge Alekhine. A new sports official worked diligently behind the scenes to undermine the original decision to have a match for the title between Bondarevskyand Lilienthal. As a result, it was announced a new title Absolute Champion of the USSR was being set up and would be contested in Leningrad and Moscow as amatch-tournament of the top six. In fact, the Absolute Championship was to be a one-off, never to be played again. Only two months after Botvinnik's success, his dreams ofchallenging Alekhine were shattered when Hitler invaded the Soviet Union.

1941 Absolute Champion of the USSR!!!1!2!3!4!5!6!Total
1 Mikhail Botvinnik ----1½½½1½1½1½1½1½0101½113½
20½½½----110½½0½½01½11½1½11
30½0½001½----½1½1½1½½½½½½10
40½0½½1½½½0½0----11½1½00½9
50½1010½0½0½½00½0----1½11
610½00½0½½½½½½11½0½00----8

Notes and References

  1. Cafferty, Bernard. (2016). The Soviet Championships. Londres: Everyman Chess. p. 46-52