1940 Iowa gubernatorial election explained

Election Name:1940 Iowa gubernatorial election
Country:Iowa
Flag Image:Flag of Iowa (variant).svg
Type:Presidential
Ongoing:no
Previous Election:1938 Iowa gubernatorial election
Previous Year:1938
Next Election:1942 Iowa gubernatorial election
Next Year:1942
Election Date:November 7, 1940
Nominee1:George A. Wilson
Party1:Republican Party (United States)
Popular Vote1:620,480
Percentage1:52.72%
Nominee2:John K. Valentine
Party2:Democratic Party (United States)
Popular Vote2:553,941
Percentage2:47.07%
Map Size:230px
Governor
Before Election:George A. Wilson
Before Party:Republican Party (United States)
After Election:George A. Wilson
After Party:Republican Party (United States)

The 1940 Iowa gubernatorial election was held on November 5, 1940. Incumbent Republican George A. Wilson defeated Democratic nominee John K. Valentine with 52.72% of the vote.

Primary elections

Primary elections were held on June 3, 1940.[1]

Democratic primary

Candidates

Results

Republican primary

Candidates

Results

General election

Candidates

Major party candidates

Other candidates

Results

Notes and References

  1. Web site: Summary of Official Canvass of Votes Cast in Iowa Primary Election . . 1940 . April 18, 2020.