1939 Wimbledon Championships – Women's singles explained

Score:6–2, 6–0
Draw:96 (10)
Seeds:8
After Year:1946
Type:grand slam

See main article: article and 1939 Wimbledon Championships.

Alice Marble defeated Kay Stammers in the final, 6–2, 6–0 to win the ladies' singles tennis title at the 1939 Wimbledon Championships.[1] Helen Moody was the defending champion, but did not compete.

Seeds

See also: 1 and 8. Alice Marble (champion)

See also: 2 and 1. Helen Jacobs (quarterfinals)

See also: 3 and 6. Hilde Sperling (semifinals)

See also: 4 and 3. Simonne Mathieu (quarterfinals)

See also: 5 and 7. Jadwiga Jędrzejowska (quarterfinals)

See also: 6 and 2. Kay Stammers (final)

See also: 7 and 5. Mary Hardwick (quarterfinals)

See also: 8 and 4. Sarah Fabyan (semifinals)

Draw

Top half

Section 4

Bottom half

Section 8

Notes and References

  1. Book: Barrett, John. Wimbledon: The Official History. 2014. Vision Sports Publishing. 9-781909-534230. 4th.