Score: | 6–2, 6–0 |
Draw: | 96 (10) |
Seeds: | 8 |
After Year: | 1946 |
Type: | grand slam |
See main article: article and 1939 Wimbledon Championships.
Alice Marble defeated Kay Stammers in the final, 6–2, 6–0 to win the ladies' singles tennis title at the 1939 Wimbledon Championships.[1] Helen Moody was the defending champion, but did not compete.
See also: 1 and 8. Alice Marble (champion)
See also: 2 and 1. Helen Jacobs (quarterfinals)
See also: 3 and 6. Hilde Sperling (semifinals)
See also: 4 and 3. Simonne Mathieu (quarterfinals)
See also: 5 and 7. Jadwiga Jędrzejowska (quarterfinals)
See also: 6 and 2. Kay Stammers (final)
See also: 7 and 5. Mary Hardwick (quarterfinals)
See also: 8 and 4. Sarah Fabyan (semifinals)