1938 Wimbledon Championships – Women's singles explained

Score:6–4, 6–0
Draw:96 (10)
Seeds:8
Type:grand slam

See main article: article and 1938 Wimbledon Championships.

Helen Moody defeated Helen Jacobs in the final, 6–4, 6–0 to win the ladies' singles tennis title at the 1938 Wimbledon Championships. This was Moody's 19th and last grand slam title, which would remain an all-time record until Margaret Court won her 20th major at the 1970 US Open.[1] Dorothy Round was the defending champion, but did not compete.

Seeds

See also: 1 and 8. Helen Moody (champion)

See also: 2 and 1. Alice Marble (semifinals)

See also: 3 and 3. Jadwiga Jędrzejowska (quarterfinals)

See also: 4 and 6. Hilde Sperling (semifinals)

See also: 5 and 2. Simonne Mathieu (quarterfinals)

See also: 6 and 7. Kay Stammers (quarterfinals)

See also: 7 and 5. Sarah Fabyan (quarterfinals)

See also: 8 and 4. Peggy Scriven (fourth round)

Draw

Top half

Section 4

Bottom half

Section 8

Notes and References

  1. Book: Barrett, John. Wimbledon: The Official History. 2014. Vision Sports Publishing. 9-781909-534230. 4th.