1938 Australian Championships – Women's singles explained

First-seeded Dorothy Bundy defeated Dorothy Stevenson 6–3, 6–2, in the final to win the women's singles tennis title at the 1938 Australian Championships.^[1]

Seeds

The seeded players are listed below. Dorothy Bundy is the champion; others show the round in which they were eliminated.

1. Dorothy Bundy (champion)
2. Nancye Wynne (semifinals)
3. Thelma Coyne (quarterfinals)
4. Joan Hartigan (quarterfinals)
5. Nell Hopman (semifinals)
6. May Hardcastle (quarterfinals)
7. Dorothy Stevenson (finalist)
8. Do Workman (quarterfinals)

Draw

Key

• Q = Qualifier
• WC = Wild card
• LL = Lucky loser
• r = Retired

Earlier rounds

Section 2

Notes and References

1. News: Americans invincible . . 25,831 . Victoria, Australia . 31 January 1938 . 15 . National Library of Australia.