1932 United States presidential election in South Carolina explained

See main article: 1932 United States presidential election.

Election Name:1932 United States presidential election in South Carolina
Country:South Carolina
Type:presidential
Ongoing:no
Previous Election:1928 United States presidential election in South Carolina
Previous Year:1928
Next Election:1936 United States presidential election in South Carolina
Next Year:1936
Election Date:November 8, 1932
Image1:FDR in 1933 (3x4).jpg
Nominee1:Franklin D. Roosevelt
Party1:Democratic Party (United States)
Home State1:New York
Running Mate1:John Nance Garner
Electoral Vote1:8
Popular Vote1:102,347
Percentage1:98.03%
Nominee2:Herbert Hoover
Party2:Republican Party (United States)
Home State2:California
Running Mate2:Charles Curtis
Electoral Vote2:0
Popular Vote2:1,978
Percentage2:1.89%
Map Size:325px
President
Before Election:Herbert Hoover
Before Party:Republican Party (United States)
After Election:Franklin D. Roosevelt
After Party:Democratic Party (United States)

The 1932 United States presidential election in South Carolina took place on November 8, 1932, as part of the 1932 United States presidential election which was held throughout all contemporary 48 states. Voters chose 8 representatives, or electors to the Electoral College, who voted for president and vice president.

South Carolina voted for the Democratic nominee, Governor Franklin D. Roosevelt of New York, over the Republican nominee, incumbent President Herbert Hoover of California. Roosevelt ran with incumbent Speaker of the House John Nance Garner of Texas, while Hoover's running mate was incumbent Vice President Charles Curtis of Kansas.

Roosevelt won South Carolina almost unanimously, taking 98.03% of the vote to Hoover's 1.89%. He swept every county in the state with more than 80% of the vote, and all but one with greater than 90%. With a victory margin of 96.14%, South Carolina proved to be Roosevelt's strongest state in this election.