1930 Tour de Hongrie explained
1930 Tour de Hongrie |
Date: | 4–8 September |
Stages: | 5 |
Distance: | 1016[1] |
Unit: | km |
Time: | 36h 29' 44" |
First: | Vasco Bergamaschi |
First Nat: | ITA |
First Natvar: | 1861 |
Second: | János Pech |
Second Nat: | HUN |
Second Natvar: | 1920 |
Third: | Andrea Minasso |
Third Nat: | ITA |
Third Natvar: | 1861 |
Team: | Postás |
Previous: | 1929 |
Next: | 1931 |
The 1930 Tour de Hongrie was the fifth edition of the Tour de Hongrie cycle race and was held from 4 to 8 September 1930. The race started and finished in Budapest. The race was won by Vasco Bergamaschi.
Route
Stages of the 1930 Tour de HongrieStage | Date | Route | Distance | Winner |
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1 | 4 September | Budapest to Debrecen | 231km (144miles) | |
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2 | 5 September | Debrecen to Hódmezővásárhely | 205km (127miles) | |
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3 | 6 September | Hódmezővásárhely to Budapest | 211km (131miles) | |
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4 | 7 September | Budapest to Keszthely | 175km (109miles) | |
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5 | 8 September | Keszthely to Budapest | 194km (121miles) | |
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Total | 1016km (631miles) | |
General classification
Final general classification[2] | |
Notes and References
- Web site: 5. Tour de Hongrie. Indul az ötnapos (1930). tdh.hu. 15 July 2019.
- Web site: 1930 Tour de Hongrie. First Cycling. 15 July 2019.