1928 Wimbledon Championships – Women's singles explained

Score:	6–2, 6–3
Draw:	80 (10)
Seeds:	8
Type:	grand slam

See main article: article and 1928 Wimbledon Championships. Helen Wills successfully defended her title, defeating Lilí de Álvarez in the final, 6–2, 6–3 to win the ladies' singles tennis title at the 1928 Wimbledon Championships.^{[1] [2]}

Seeds

See also: 1 and 1. Helen Wills (champion)

See also: 2 and 5. Lilí de Álvarez (final)

See also: 3 and 7. Eileen Bennett (quarterfinals)

See also: 4 and 3. Elizabeth Ryan (semifinals)

See also: 5 and 4. Kea Bouman (third round)

See also: 6 and 2. Phoebe Watson (quarterfinals)

See also: 7 and 6. Cilly Aussem (quarterfinals)

See also: 8 and 8. Helen Jacobs (third round)

Draw

Top half

Section 4

Bottom half

Section 8

Notes and References

1. Book: Barrett, John. Wimbledon: The Official History. 2014. Vision Sports Publishing. 9-781909-534230. 4th.
2. Helen Wills - Still Supreme 1928. British Pathé. 12 July 1928. Wimbledon, London.. Film id 732.26.