1928 United States presidential election in South Carolina explained

See main article: 1928 United States presidential election.

Election Name:1928 United States presidential election in South Carolina
Country:South Carolina
Type:presidential
Ongoing:no
Previous Election:1924 United States presidential election in South Carolina
Previous Year:1924
Next Election:1932 United States presidential election in South Carolina
Next Year:1932
Election Date:November 6, 1928
Image1:Unsuccessful 1928.jpg
Nominee1:Al Smith
Party1:Democratic Party (United States)
Home State1:New York
Running Mate1:Joseph Taylor Robinson
Electoral Vote1:9
Popular Vote1:62,700
Percentage1:91.39%
Nominee2:Herbert Hoover
Party2:Republican Party (United States)
Home State2:California
Running Mate2:Charles Curtis
Electoral Vote2:0
Popular Vote2:5,858
Percentage2:8.54%
Map Size:325px
President
Before Election:Calvin Coolidge
Before Party:Republican Party (United States)
After Election:Herbert Hoover
After Party:Republican Party (United States)
Flag Year:1909

The 1928 United States presidential election in South Carolina took place on November 6, 1928, as part of the 1928 United States presidential election which was held throughout all contemporary 48 states. Voters chose 9 representatives, or electors to the Electoral College, who voted for president and vice president.

South Carolina voted for the Democratic nominee, Governor Alfred E. Smith of New York, over the Republican nominee, former Secretary of Commerce Herbert Hoover of California. Smith ran with Senator Joseph Taylor Robinson of Arkansas, while Hoover's running mate was Senate Majority Leader Charles Curtis of Kansas.

In the midst of a third Republican landslide, Smith won South Carolina by a margin of 82.85%. Not only was South Carolina Al Smith's best state, it was the largest margin of victory by both Al Smith and Herbert Hoover that year, largely accredited to Southern politics being heavily democratic and low voter turnout.