See main article: 1928 United States presidential election.
| Election Name: | 1928 United States presidential election in Rhode Island |
| Country: | Rhode Island |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1924 United States presidential election in Rhode Island |
| Previous Year: | 1924 |
| Next Election: | 1932 United States presidential election in Rhode Island |
| Next Year: | 1932 |
| Election Date: | November 6, 1928 |
| Image1: | Unsuccessful 1928.jpg |
| Nominee1: | Al Smith |
| Party1: | Democratic Party (United States) |
| Home State1: | New York |
| Running Mate1: | Joseph Taylor Robinson |
| Electoral Vote1: | 5 |
| Popular Vote1: | 118,973 |
| Percentage1: | 50.16% |
| Nominee2: | Herbert Hoover |
| Party2: | Republican Party (United States) |
| Home State2: | California |
| Running Mate2: | Charles Curtis |
| Electoral Vote2: | 0 |
| Popular Vote2: | 117,522 |
| Percentage2: | 49.55% |
| Map Size: | 250px |
| President | |
| Before Election: | Calvin Coolidge |
| Before Party: | Republican Party (United States) |
| After Election: | Herbert Hoover |
| After Party: | Republican Party (United States) |
The 1928 United States presidential election in Rhode Island took place on November 6, 1928, as part of the 1928 United States presidential election which was held throughout all contemporary 48 states. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.
Rhode Island voted for the Democratic nominee, Governor Alfred E. Smith of New York, over the Republican nominee, former Secretary of Commerce Herbert Hoover of California. Smith's running mate was Senator Joseph Taylor Robinson of Arkansas, while Hoover's running mate was Senate Majority Leader Charles Curtis of Kansas.
Smith won Rhode Island by a very narrow margin of 0.61%, making him the first Democratic presidential candidate since Woodrow Wilson in 1912 to carry the state, as well as the first to win an absolute majority of the vote since Franklin Pierce in 1852. Although Hoover won more counties than Smith, key to Smith's victory was his appeal to "ethnic white" Roman Catholic voters in Providence County and Bristol County. Rhode Island was the only state save adjacent Massachusetts (another state with a large Catholic population) outside the Democratic "Solid South" that voted for Smith in 1928. The former had not voted Democratic since 1912 and the latter since 1836. This was the second of three times that the state voted differently than Minnesota, along with 1912 and 1984.
Despite winning in a landslide nationally, Hoover became the first Republican to ever win the presidency without carrying Rhode Island. Given the scale of Hoover's win, Rhode Island weighed in as 18 percentage points more Democratic than the United States at large. Hoover also became the first Republican to ever win without carrying Providence and Bristol counties. Beginning in 1928, Rhode Island would transition from a strongly Yankee Republican state into a Democratic-leaning state. Since then, Republicans have only carried the state four times, all in Republican landslide years: 1952, 1956, 1972, and 1984.
| 1928 United States presidential election in Rhode Island (by county) [1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| County | Al SmithDemocratic | Herbert HooverRepublican | Other candidatesVarious parties | Total | ||||
| % | % | % | ||||||
| Bristol | 51.8% | 4,080 | 48.0% | 3,780 | 0.2% | 13 | 7,873 | |
| Kent | 39.3% | 7,460 | 60.4% | 11,487 | 0.3% | 58 | 19,005 | |
| Newport | 43.9% | 6,748 | 55.8% | 8,578 | 0.2% | 33 | 15,359 | |
| Providence | 52.9% | 97,185 | 46.8% | 85,884 | 0.3% | 568 | 183,637 | |
| Washington | 30.9% | 3,500 | 68.8% | 7,793 | 0.2% | 27 | 11,320 | |