1928 French Championships – Women's singles explained

Score:	6–1, 6–2
Draw:	37
Seeds:	8

First-seeded Helen Wills defeated Eileen Bennett 6–1, 6–2 in the final to win the women's singles tennis title at the 1928 French Championships.^[1] The draw consisted of 37 players of which 8 were seeded.

Seeds

The seeded players are listed below. Helen Wills is the champion; others show the round in which they were eliminated.

1. Helen Wills (champion)
2. Suzanne Devé (second round)
3. Kea Bouman (semifinals)
4. Daphne Akhurst (quarterfinals)
5. Elisabeth Macready (second round)
6. Lilly De Alvarez (first round)
7. Marguerite Bordes (third round)
8. Eileen Bennett (finalist)

Draw

Key

• Q = Qualifier
• WC = Wild card
• LL = Lucky loser
• r = Retired

Earlier rounds

Section 4

Notes and References

1. Book: Collins, Bud. The Bud Collins History of Tennis. 2010. New Chapter Press. [New York]. 978-0942257700. 2nd. 393.