1928 Australian Championships – Women's singles explained

Score:	7–5, 6–2
Draw:	19
Seeds:	4
Type:	grand slam

Daphne Akhurst defeated Esna Boyd 7–5, 6–2, in the final to win the women's singles tennis title at the 1928 Australian Championships.

Seeds

The seeded players are listed below. Daphne Akhurst is the champion; others show the round in which they were eliminated.

1. Esna Boyd (finalist)
2. Daphne Akhurst (champion)
3. Louie Bickerton (semifinals)
4. Sylvia Harper (second round)

Draw

Key

• Q = Qualifier
• WC = Wild card
• LL = Lucky loser
• r = Retired

Earlier rounds

Section 2

See also

• 1928 Australian Championships – Men's singles

Notes

• In an original draw ^[1] Le Messurier and Weston – both representatives of South Australia – have been drawn together in the first round (Freudenstein received a bye into the second round to play against Waterhouse). This was protested by the South Australian Council as being against the regulations.^[2]
• This is most confusing one. No source gives an information about such a draw, let alone the result.

External links

• • http://trove.nla.gov.au/newspaper/article/245503202 Source for seedings

Notes and References

1. News: Lawn Tennis . . 18 January 1928 . 19 . National Library of Australia.
2. News: Sports and Pastimes . . Adelaide, Australia . 20 January 1928 . 6 . National Library of Australia.