1924 Iowa gubernatorial election explained

Election Name:1924 Iowa gubernatorial election
Country:Iowa
Flag Image:Flag of Iowa (variant).svg
Type:Presidential
Ongoing:no
Previous Election:1922 Iowa gubernatorial election
Previous Year:1922
Next Election:1926 Iowa gubernatorial election
Next Year:1926
Election Date:November 4, 1924
Nominee1:John Hammill
Party1:Republican Party (United States)
Popular Vote1:604,624
Percentage1:72.72%
Nominee2:James C. Murtagh
Party2:Democratic Party (United States)
Popular Vote2:226,850
Percentage2:27.28%
Map Size:230px
Governor
Before Election:Nathan E. Kendall
Before Party:Republican Party (United States)
After Election:John Hammill
After Party:Republican Party (United States)

The 1924 Iowa gubernatorial election was held on November 4, 1924. Republican nominee John Hammill defeated Democratic nominee James C. Murtagh with 72.72% of the vote.

Primary elections

Primary elections were held on June 2, 1924.[1]

Republican primary

Candidates

Results

General election

Candidates

Results

Notes and References

  1. Book: Guide to U.S. elections - CQ Press, Congressional Quarterly, inc . 2005 . CQ Press . 9781568029818 . June 16, 2020.