1920 United States presidential election in Delaware explained

See main article: 1920 United States presidential election.

Election Name:1920 United States presidential election in Delaware
Country:Delaware
Type:presidential
Ongoing:no
Previous Election:1916 United States presidential election in Delaware
Previous Year:1916
Next Election:1924 United States presidential election in Delaware
Next Year:1924
Election Date:November 2, 1920
Image1:Warren G Harding-Harris & Ewing crop.jpg
Nominee1:Warren G. Harding
Party1:Republican Party (United States)
Home State1:Ohio
Running Mate1:Calvin Coolidge
Electoral Vote1:3
Popular Vote1:52,858
Percentage1:55.71%
Nominee2:James M. Cox
Party2:Democratic Party (United States)
Home State2:Ohio
Running Mate2:Franklin D. Roosevelt
Electoral Vote2:0
Popular Vote2:39,911
Percentage2:42.07%
Map Size:210px
President
Before Election:Woodrow Wilson
Before Party:Democratic Party (United States)
After Election:Warren G. Harding
After Party:Republican Party (United States)

The 1920 United States presidential election in Delaware took place on November 2, 1920. All contemporary 48 states were part of the 1920 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

Delaware was won by the Republican nominee, Senator Warren G. Harding of Ohio, over the Democratic nominee, Governor James M. Cox of Ohio. Harding ran with Governor Calvin Coolidge of Massachusetts, while Cox ran with future President Franklin D. Roosevelt of New York.

See also