1916 Georgia gubernatorial election explained

Election Name:1916 Georgia gubernatorial election
Country:Georgia (U.S. state)
Type:Presidential
Ongoing:no
Previous Election:1914 Georgia gubernatorial election
Previous Year:1914
Next Election:1918 Georgia gubernatorial election
Next Year:1918
Election Date:7 November 1916
Nominee1:Hugh Dorsey
Party1:Democratic Party (United States)
Popular Vote1:139,772
Percentage1:96.45%
Nominee2:Roscoe Pickett
Party2:Republican Party (United States)
Popular Vote2:4,217
Percentage2:2.91%
Governor
Before Election:Nathaniel Edwin Harris
Before Party:Democratic Party (United States)
After Election:Hugh Dorsey
After Party:Democratic Party (United States)

The 1916 Georgia gubernatorial election was held on 7 November 1916 in order to elect the Governor of Georgia. Democratic nominee Hugh Dorsey overwhelmingly defeated Republican nominee Roscoe Pickett and Socialist party candidate Thomas M. Taylor.[1] It was the first gubernatorial election to be contested by the Republican Party since 1876, and the last they would contest until 1966.

General election

On election day, 7 November 1916, Democratic nominee Hugh Dorsey won the election by a margin of 135,555 votes against his foremost opponent Republican nominee Roscoe Pickett, thereby holding Democratic control over the office of Governor. Dorsey was sworn in as the 62nd Governor of Georgia (US State) on 30 June 1917.[2]

Results

Notes and References

  1. Web site: Gov. Hugh Manson Dorsey . nga.org . 30 November 2023.
  2. Web site: GA Governor . ourcampaigns.com . 30 October 2017 . 30 November 2023.