1912 Iowa gubernatorial election explained

Election Name:1912 Iowa gubernatorial election
Country:Iowa
Type:Presidential
Ongoing:no
Previous Election:1910 Iowa gubernatorial election
Previous Year:1910
Next Election:1914 Iowa gubernatorial election
Next Year:1914
Election Date:November 5, 1912
Image1:Lieutenant Governor George W. Clarke (1).jpg
Nominee1:George W. Clarke
Party1:Republican Party (United States)
Popular Vote1:184,150
Percentage1:39.93%
Nominee2:Edward G. Dunn
Party2:Democratic Party (United States)
Popular Vote2:182,449
Percentage2:39.56%
Image3:3x4.svg
Nominee3:John L. Stevens
Party3:Progressive Party (United States, 1912)
Popular Vote3:71,879
Percentage3:15.59%
Map Size:230px
Governor
Before Election:Beryl F. Carroll
Before Party:Republican Party (United States)
After Election:George W. Clarke
After Party:Republican Party (United States)

The 1912 Iowa gubernatorial election was held on November 5, 1912. Republican nominee George W. Clarke defeated Democratic nominee Edward G. Dunn with 39.93% of the vote.

Primary elections

Primary elections were held on June 3, 1912.[1]

Democratic primary

Candidates

Results

Republican primary

Candidates

Results

General election

Candidates

Major party candidates

Other candidates

Results

Notes and References

  1. Book: Guide to U.S. elections - CQ Press, Congressional Quarterly, inc . 2005 . CQ Press . 9781568029818 . July 31, 2020.