1910 Vermont gubernatorial election explained

Election Name:1910 Vermont gubernatorial election
Country:Vermont
Flag Year:1837
Type:presidential
Ongoing:no
Previous Election:1908 Vermont gubernatorial election
Previous Year:1908
Next Election:1912 Vermont gubernatorial election
Next Year:1912
Image1:File:John Abner Mead USA politician Governor Vermont-crop.jpg
Nominee1:John A. Mead
Party1:Republican Party (United States)
Popular Vote1:35,263
Percentage1:64.2%
Party2:Democratic Party (United States)
Nominee2:Charles D. Watson
Popular Vote2:17,425
Percentage2:31.7%
Governor
Before Election:George H. Prouty
Before Party:Republican Party (United States)
After Election:John A. Mead
After Party:Republican Party (United States)

The 1910 Vermont gubernatorial election took place on September 6, 1910. Incumbent Republican George H. Prouty, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate John A. Mead defeated Democratic candidate Charles D. Watson to succeed him.

Marshall J. Hapgood, who ran a quixotic campaign for the Republican gubernatorial nomination, filed Vermont's first-ever campaign finance report, which indicated that he spent $103.76 .[2]

Notes and References

  1. Web site: Hand. Samuel B.. Mountain Rule Revisited. Vermont Historical Society. 1 January 2015.
  2. News: September 18, 1994 . Politics and Power Forever Linked With Money . 47 . . live . https://web.archive.org/web/20221209010243/https://www.newspapers.com/clip/114326551/rutland-daily-herald/ . December 9, 2022 . Newspapers.com.