1908 United States presidential election in Texas explained

See main article: 1908 United States presidential election.

Election Name:1908 United States presidential election in Texas
Country:Texas
Flag Year:1908
Type:presidential
Ongoing:no
Previous Election:1904 United States presidential election in Texas
Previous Year:1904
Next Election:1912 United States presidential election in Texas
Next Year:1912
Election Date:November 3, 1908
Image1:Unsuccessful 1908.jpg
Nominee1:William Jennings Bryan
Party1:Democratic Party (United States)
Home State1:Nebraska
Running Mate1:John W. Kern
Electoral Vote1:18
Popular Vote1:217,302
Percentage1:73.97%
Nominee2:William Howard Taft
Party2:Republican Party (United States)
Home State2:Ohio
Running Mate2:James S. Sherman
Electoral Vote2:0
Popular Vote2:65,666
Percentage2:22.35%
Map Size:350px
President
Before Election:Theodore Roosevelt
Before Party:Republican Party (United States)
After Election:William Howard Taft
After Party:Republican Party (United States)

The 1908 United States presidential election in Texas took place on November 3, 1908. Voters chose 18 representatives, or electors to the Electoral College, who voted for president and vice president.

Texas overwhelmingly voted for the Democratic nominee, former U.S. Representative William Jennings Bryan, over the Republican nominee, Secretary of War William Howard Taft. Bryan won Texas by a landslide margin of 51.62%.

Bryan had previously won Texas against William McKinley in both 1896 and 1900. With 73.97 percent of the popular vote, Texas would also prove to be Bryan's fourth strongest victory in terms of percentage in the popular vote only after South Carolina, Mississippi and Louisiana.[1]

See also

Notes and References

  1. Web site: 1908 Presidential Election Statistics. Dave Leip's Atlas of U.S. Presidential Elections. 2018-03-05.