1905 Paris–Roubaix Explained

1905 Paris–Roubaix
Date:23 April 1905
Stages:1
Distance:268
Unit:km
Time:8h 4' 15"
Speed:33.206
First:Louis Trousselier
First Nat:FRA
Second:René Pottier
Second Nat:FRA
Third:Henri Cornet
Third Nat:FRA
Previous:1904
Next:1906

The 1905 Paris–Roubaix was the tenth edition of the Paris–Roubaix, a classic one-day cycle race in France. The single day event was held on 23 April 1905 and stretched 268km (167miles) from Paris to its end in a velodrome in Roubaix.[1] The winner was Louis Trousselier from France.[2]

Results

Final results (1–10)!Rank!Cyclist!Time
1
2
3
4
5
6
7
8
9
10

Notes and References

  1. Web site: 10th Paris – Roubaix, 1905 . 27 February 2015 . bikeraceinfo.
  2. Web site: 1905 » 10th Paris – Roubaix . 27 February 2015 . ProCyclingStats.