See main article: 1904 United States presidential election.
| Election Name: | 1904 United States presidential election in Rhode Island |
| Country: | Rhode Island |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1900 United States presidential election in Rhode Island |
| Previous Year: | 1900 |
| Next Election: | 1908 United States presidential election in Rhode Island |
| Next Year: | 1908 |
| Election Date: | November 8, 1904 |
| Image1: | President Roosevelt - Pach Bros (cropped 3x4).jpg |
| Nominee1: | Theodore Roosevelt |
| Party1: | Republican Party (United States) |
| Home State1: | New York |
| Running Mate1: | Charles W. Fairbanks |
| Electoral Vote1: | 4 |
| Popular Vote1: | 41,605 |
| Percentage1: | 60.60% |
| Nominee2: | Alton B. Parker |
| Party2: | Democratic Party (United States) |
| Home State2: | New York |
| Running Mate2: | Henry G. Davis |
| Electoral Vote2: | 0 |
| Popular Vote2: | 24,839 |
| Percentage2: | 36.18% |
| Map Size: | 250px |
| President | |
| Before Election: | Theodore Roosevelt |
| Before Party: | Republican Party (United States) |
| After Election: | Theodore Roosevelt |
| After Party: | Republican Party (United States) |
The 1904 United States presidential election in Rhode Island took place on November 8, 1904, as part of the 1904 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
Rhode Island overwhelmingly voted for the Republican nominee, President Theodore Roosevelt, over the Democratic nominee, former Chief Judge of New York Court of Appeals Alton B. Parker. Roosevelt won Rhode Island by a margin of 24.42%.