1904 United States presidential election in Massachusetts explained

See main article: 1904 United States presidential election.

Election Name:1904 United States presidential election in Massachusetts
Country:Massachusetts
Type:presidential
Ongoing:no
Previous Election:1900 United States presidential election in Massachusetts
Previous Year:1900
Next Election:1908 United States presidential election in Massachusetts
Next Year:1908
Turnout:67.6%[1] 0.2 pp
Election Date:November 8, 1904
Image1:Theodore Roosevelt by the Pach Bros (cropped 3x4).jpg
Nominee1:Theodore Roosevelt
Party1:Republican Party (United States)
Home State1:New York
Running Mate1:Charles W. Fairbanks
Electoral Vote1:16
Popular Vote1:257,822
Percentage1:57.92%
Nominee2:Alton B. Parker
Party2:Democratic Party (United States)
Home State2:New York
Running Mate2:Henry G. Davis
Electoral Vote2:0
Popular Vote2:165,746
Percentage2:37.24%
Map Size:350px
President
Before Election:Theodore Roosevelt
Before Party:Republican Party (United States)
After Election:Theodore Roosevelt
After Party:Republican Party (United States)

The 1904 United States presidential election in Massachusetts took place on November 8, 1904, as part of the 1904 United States presidential election. Voters chose 16 representatives, or electors to the Electoral College, who voted for president and vice president.

Massachusetts voted for the Republican nominee, President Theodore Roosevelt, over the Democratic nominee, former Chief Judge of New York Court of Appeals Alton B. Parker. Roosevelt won the state by a margin of 20.68%.

See also

Notes and References

  1. Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.