1896 United States House of Representatives elections in California explained
Election Name: | 1896 United States House of Representatives elections in California |
Country: | California |
Type: | legislative |
Ongoing: | no |
Previous Election: | 1894 United States House of Representatives elections in California |
Previous Year: | 1894 |
Next Election: | 1898 United States House of Representatives elections in California |
Next Year: | 1898 |
Seats For Election: | All 7 California seats to the United States House of Representatives |
Party1: | Republican Party (United States) |
Last Election1: | 6 |
Seats1: | 3 |
Seat Change1: | 3 |
Popular Vote1: | 128,941 |
Percentage1: | 46.4% |
Party2: | Democratic Party (United States) |
Last Election2: | 1 |
Seats2: | 2 |
Seat Change2: | 1 |
Popular Vote2: | 86,449 |
Percentage2: | 31.1% |
Party3: | Populist Party (United States) |
Last Election3: | 0 |
Seats3: | 2 |
Seat Change3: | 2 |
Popular Vote3: | 53,662 |
Percentage3: | 19.3% |
Map Size: | 250px |
The United States House of Representatives elections in California, 1896 was an election for California's delegation to the United States House of Representatives, which occurred as part of the general election of the House of Representatives on November 3, 1896. Republicans lost one seat to the Democrats and two to the Populists.
Overview
Delegation Composition
Pre-election | Seats
|
| Republican-Held | 6 |
| Democratic-Held | 1 |
|
Post-election | Seats
|
| Republican-Held | 3 |
| Democratic-Held | 2 |
| Populist-Held | 2 |
|
Results
District 7
See also
References
External links