| Election Name: | 1896 Rhode Island gubernatorial election |
| Country: | Rhode Island |
| Flag Year: | 1882 |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1895 Rhode Island gubernatorial election |
| Previous Year: | 1895 |
| Next Election: | 1897 Rhode Island gubernatorial election |
| Next Year: | 1897 |
| Election Date: | April 1, 1896 |
| Nominee1: | Charles W. Lippitt |
| Party1: | Republican Party (United States) |
| Popular Vote1: | 28,472 |
| Percentage1: | 56.40% |
| Nominee2: | George L. Littlefield |
| Party2: | Democratic Party (United States) |
| Popular Vote2: | 17,061 |
| Percentage2: | 33.79% |
| Image3: | PRO |
| Nominee3: | Thomas H. Peabody |
| Party3: | Prohibition Party (United States) |
| Popular Vote3: | 2,950 |
| Percentage3: | 5.84% |
| Governor | |
| Before Election: | Charles W. Lippitt |
| Before Party: | Republican Party (United States) |
| After Election: | Charles W. Lippitt |
| After Party: | Republican Party (United States) |
The 1896 Rhode Island gubernatorial election was held on April 1, 1896. Incumbent Republican Charles W. Lippitt defeated Democratic nominee George L. Littlefield with 56.40% of the vote.
Major party candidates
Other candidates