1896 Georgia gubernatorial election explained

Election Name:1896 Georgia gubernatorial election
Country:Georgia (U.S. state)
Type:Presidential
Ongoing:no
Previous Election:1894 Georgia gubernatorial election
Previous Year:1894
Next Election:1898 Georgia gubernatorial election
Next Year:1898
Election Date:7 October 1896
Image1:William Yates Atkinson.jpg
Nominee1:William Yates Atkinson
Party1:Democratic Party (United States)
Popular Vote1:123,206
Percentage1:58.90%
Nominee2:Seaborn Wright
Party2:People's Party (United States)
Popular Vote2:85,981
Percentage2:41.10%
Governor
Before Election:William Yates Atkinson
Before Party:Democratic Party (United States)
After Election:William Yates Atkinson
After Party:Democratic Party (United States)

The 1896 Georgia gubernatorial election was held on 7 October 1896 in order to elect the Governor of Georgia. Democratic nominee and incumbent Governor William Yates Atkinson defeated People's Party nominee Seaborn Wright.[1]

General election

On election day, 7 October 1896, Democratic nominee William Yates Atkinson won re-election with a margin of 37,225 votes against his opponent People's Party nominee Seaborn Wright, thereby holding Democratic control over the office of Governor. Atkinson was sworn in for his second term on 29 October 1896.[2]

Results

Notes and References

  1. Web site: Gov. William Yates Atkinson . 5 January 2024 . National Governors Association.
  2. Web site: GA Governor . ourcampaigns.com . 8 November 2023 . 5 January 2024.