1896 Belgian general election explained

Country:Belgium
Type:parliamentary
Previous Election:1894 Belgian general election
Previous Year:1894
Next Election:1898 Belgian general election
Next Year:1898
Seats For Election:77 of the 152 seats in the Chamber of Representatives
Election Date:5 July 1896
Image1:Paul_de_Smet_de_Naeyer.jpg
Leader1:Paul de Smet de Naeyer
Party1:Catholic Party (Belgium)
Seats1:72
Popular Vote1:492,541
Percentage1:49.68%
Party2:Liberal Party (Belgium)
Seats2:1
Popular Vote2:193,563
Percentage2:19.52%
Image3:3x4.svg
Leader3:N/A
Party3:LiberalSocialist
Seats3:4
Popular Vote3:49,614
Percentage3:5.00%
Color3:800080
Government
Posttitle:Government after election
Before Election:de Smet de Naeyer I
Before Party:Catholic Party (Belgium)
After Election:de Smet de Naeyer I
After Party:Catholic Party (Belgium)

Partial legislative elections were held in Belgium on 5 and 12 July 1896.[1] Under the alternating system, elections were held in only five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders. Only 77 seats out of the 152 seats in the Chamber of Representatives were up for election. The Catholic Party retained their absolute majority.[2]

The Liberal Party, who lost two-thirds of their seats in the previous elections, saw their number of seats decrease further.

Notes and References

  1. Book: Dieter Nohlen

    . Elections in Europe: A data handbook . Nohlen . Dieter . Dieter Nohlen . Stöver . Philip . 31 May 2010 . Nomos Verlagsgesellschaft . 289 . 978-3-8329-5609-7.

  2. Nohlen & Stöver, p307