| Election Name: | 1895 Rhode Island gubernatorial election |
| Country: | Rhode Island |
| Flag Year: | 1882 |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1894 Rhode Island gubernatorial election |
| Previous Year: | 1894 |
| Next Election: | 1896 Rhode Island gubernatorial election |
| Next Year: | 1896 |
| Election Date: | April 3, 1895 |
| Nominee1: | Charles W. Lippitt |
| Party1: | Republican Party (United States) |
| Popular Vote1: | 25,098 |
| Percentage1: | 56.89% |
| Nominee2: | George L. Littlefield |
| Party2: | Democratic Party (United States) |
| Popular Vote2: | 14,289 |
| Percentage2: | 32.39% |
| Image3: | PRO |
| Nominee3: | Smith Quimby |
| Party3: | Prohibition Party (United States) |
| Popular Vote3: | 2,624 |
| Percentage3: | 5.95% |
| Governor | |
| Before Election: | Daniel Russell Brown |
| Before Party: | Republican Party (United States) |
| After Election: | Charles W. Lippitt |
| After Party: | Republican Party (United States) |
The 1895 Rhode Island gubernatorial election was held on April 3, 1895. Republican nominee Charles W. Lippitt defeated Democratic nominee George L. Littlefield with 56.89% of the vote.
Major party candidates
Other candidates