1894 Maine gubernatorial election explained

Election Name:1894 Maine gubernatorial election
Country:Maine
Type:Presidential
Ongoing:no
Previous Election:1892 Maine gubernatorial election
Previous Year:1892
Next Election:1896 Maine gubernatorial election
Next Year:1896
Election Date:10 September 1894
Nominee1:Henry B. Cleaves
Party1:Republican Party (United States)
Popular Vote1:69,322
Percentage1:64.31%
Nominee2:Charles F. Johnson
Party2:Democratic Party (United States)
Popular Vote2:30,405
Percentage2:28.21%
Map Size:300px
Governor
Before Election:Henry B. Cleaves
Before Party:Republican Party (United States)
After Election:Henry B. Cleaves
After Party:Republican Party (United States)

The 1894 Maine gubernatorial election was held on 10 September 1894 in order to elect the Governor of Maine. Incumbent Republican Governor Henry B. Cleaves won re-election against Democratic nominee Charles F. Johnson, Populist nominee Luther C. Bateman and Prohibition nominee Ira G. Hersey in a rematch of the previous election.[1]

General election

On election day, 10 September 1894, incumbent Republican Governor Henry B. Cleaves won re-election by a margin of 38,917 votes against his foremost opponent Democratic nominee Charles F. Johnson, thereby retaining Republican control over the office of governor. Cleaves was sworn in for his second term on 6 January 1895.[2]

Results

Notes and References

  1. Web site: Gov. Henry Bradstreet Cleaves . nga.org . 21 April 2024.
  2. Web site: ME Governor . ourcampaigns.com . 6 February 2024 . 21 April 2024.