See main article: 1892 United States presidential election.
Election Name: | 1892 United States presidential election in Massachusetts |
Country: | Massachusetts |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1888 United States presidential election in Massachusetts |
Previous Year: | 1888 |
Next Election: | 1896 United States presidential election in Massachusetts |
Next Year: | 1896 |
Turnout: | 74.6[1] 2.9 pp |
Election Date: | November 8, 1892 |
Image1: | Benjamin Harrison 1896.jpg |
Nominee1: | Benjamin Harrison |
Party1: | Republican Party (United States) |
Home State1: | Indiana |
Running Mate1: | Whitelaw Reid |
Electoral Vote1: | 15 |
Popular Vote1: | 202,814 |
Percentage1: | 51.87% |
Nominee2: | Grover Cleveland |
Party2: | Democratic Party (United States) |
Home State2: | New York |
Running Mate2: | Adlai Stevenson I |
Electoral Vote2: | 0 |
Popular Vote2: | 176,813 |
Percentage2: | 45.22% |
Map Size: | 350px |
President | |
Before Election: | Benjamin Harrison |
Before Party: | Republican Party (United States) |
After Election: | Grover Cleveland |
After Party: | Democratic Party (United States) |
The 1892 United States presidential election in Massachusetts took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for president and vice president.
Massachusetts voted for the Republican nominee, incumbent President Benjamin Harrison, over the Democratic nominee, former President Grover Cleveland, who was running for a second, non-consecutive term. Harrison won the state by a narrow margin of 6.65%.
With 51.87% of the popular vote, Massachusetts would prove to be Harrison's third strongest victory in terms of percentage in the popular vote after neighboring Vermont and Maine.[2]
As of 2020, this remains the last presidential election in which Massachusetts voted Republican while neighboring New York voted Democratic.