1892 Maine gubernatorial election explained

Election Name:1892 Maine gubernatorial election
Country:Maine
Type:Presidential
Ongoing:no
Previous Election:1890 Maine gubernatorial election
Previous Year:1890
Next Election:1894 Maine gubernatorial election
Next Year:1894
Election Date:12 September 1892
Nominee1:Henry B. Cleaves
Party1:Republican Party (United States)
Popular Vote1:67,900
Percentage1:52.13%
Nominee2:Charles F. Johnson
Party2:Democratic Party (United States)
Popular Vote2:55,397
Percentage2:42.53%
Map Size:300px
Governor
Before Election:Edwin C. Burleigh
Before Party:Republican Party (United States)
After Election:Henry B. Cleaves
After Party:Republican Party (United States)

The 1892 Maine gubernatorial election was held on 12 September 1892 in order to elect the Governor of Maine. Republican nominee and former Attorney General of Maine Henry B. Cleaves defeated Democratic nominee Charles F. Johnson, Prohibition nominee Timothy B. Hussey, Populist nominee Luther C. Bateman and Labor nominee E. F. Knowlton.[1]

General election

On election day, 12 September 1892, Republican nominee Henry B. Cleaves won the election by a margin of 12,503 votes against his foremost opponent Democratic nominee Charles F. Johnson, thereby retaining Republican control over the office of governor. Cleaves was sworn in as the 43th Governor of Maine on 4 January 1893.[2]

Results

Notes and References

  1. Web site: Gov. Henry Bradstreet Cleaves . nga.org . 21 April 2024.
  2. Web site: ME Governor . ourcampaigns.com . 6 February 2024 . 21 April 2024.