| Election Name: | 1891 Iowa gubernatorial election |
| Country: | Iowa |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1889 Iowa gubernatorial election |
| Previous Year: | 1889 |
| Next Election: | 1893 Iowa gubernatorial election |
| Next Year: | 1893 |
| Election Date: | November 3, 1891 |
| Nominee1: | Horace Boies |
| Party1: | Democratic Party (United States) |
| Popular Vote1: | 207,594 |
| Percentage1: | 49.40% |
| Nominee2: | Herman C. Wheeler |
| Party2: | Republican Party (United States) |
| Popular Vote2: | 199,381 |
| Percentage2: | 47.45% |
| Map Size: | 240px |
| Governor | |
| Before Election: | Horace Boies |
| Before Party: | Democratic Party (United States) |
| After Election: | Horace Boies |
| After Party: | Democratic Party (United States) |
The 1891 Iowa gubernatorial election was held on November 3, 1891. Incumbent Democrat Horace Boies defeated Republican nominee Herman C. Wheeler with 49.40% of the vote.
Major party candidates
Other candidates