1890 United States House of Representatives election in Wyoming explained

Election Name:1890 United States House of Representatives elections in Wyoming
Country:Wyoming
Type:presidential
Ongoing:No
Next Election:United States House of Representatives election in Wyoming, 1892
Next Year:1892
Image1:Senator Clarence Don Clark3.jpg
Nominee1:Clarence D. Clark
Party1:Republican Party (US)
Popular Vote1:8,751
Percentage1:58.46%
Nominee2:George T. Beck
Party2:Democratic Party (US)
Popular Vote2:6,219
Percentage2:41.54%
U.S. Representative
After Election:Clarence D. Clark
After Party:Republican Party (US)

There were two United States House of Representatives elections in Wyoming in 1890, both held on September 11, 1890. The first was for the 51st United States Congress, with a term expiring on March 4, 1891; this election was necessary due to Wyoming's admittance to the Union as the 44th state earlier in 1890. The second election was for the full term in the 52nd United States Congress beginning on March 4, 1891. Republican lawyer Clarence D. Clark defeated Democratic George T. Beck with about 58% of the vote in both elections and became the first person to represent Wyoming in the House of Representatives.