| Election Name: | 1890 New Hampshire gubernatorial election |
| Country: | New Hampshire |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1888 New Hampshire gubernatorial election |
| Previous Year: | 1888 |
| Next Election: | 1892 New Hampshire gubernatorial election |
| Next Year: | 1892 |
| Election Date: | November 4, 1890 |
| Nominee1: | Hiram A. Tuttle |
| Party1: | Republican Party (United States) |
| Popular Vote1: | 42,479 |
| Percentage1: | 49.26% |
| Nominee2: | Charles H. Amsden |
| Party2: | Democratic Party (United States) |
| Popular Vote2: | 42,386 |
| Percentage2: | 49.15% |
| Map Size: | 245px |
| Governor | |
| Before Election: | David H. Goodell |
| Before Party: | Republican Party (United States) |
| After Election: | Hiram A. Tuttle |
| After Party: | Republican Party (United States) |
The 1890 New Hampshire gubernatorial election was held on November 4, 1890. Republican nominee Hiram A. Tuttle defeated Democratic nominee Charles H. Amsden with 49.26% of the vote.
Major party candidates
Other candidates