| Election Name: | 1890 Belgian general election |
| Country: | Belgium |
| Type: | parliamentary |
| Previous Election: | 1888 Belgian general election |
| Previous Year: | 1888 |
| Next Election: | 1892 Belgian general election |
| Next Year: | 1892 |
| Seats For Election: | 69 of the 138 seats in the Chamber of Representatives |
| Majority Seats: | 70 |
| Leader1: | Auguste Beernaert |
| Leaders Seat1: | Candidate for PM |
| Party1: | Catholic Party (Belgium) |
| Seats Before1: | 98 seats |
| Seats1: | 29 |
| Seats After1: | 94 |
| Seat Change1: | 4 |
| Popular Vote1: | 17,253 |
| Percentage1: | 45.15% |
| Party2: | Liberal Party (Belgium) |
| Seats Before2: | 40 seats |
| Seats2: | 40 |
| Seats After2: | 44 |
| Seat Change2: | 4 |
| Popular Vote2: | 20,829 |
| Percentage2: | 54.51% |
| Government | |
| Posttitle: | Government after election |
| Before Election: | Beernaert |
| Before Party: | Catholic Party (Belgium) |
| After Election: | Beernaert |
| After Party: | Catholic Party (Belgium) |
Partial general elections were held in Belgium on 10 June 1890.[1] [2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 94 of the 138 seats.[2]
Under the alternating system, elections were held in only four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders. Thus, only 69 seats out of the 138 were up for election. Additionally, a special election was held in Neufchâteau on 3 June 1890.[3]
The distribution of seats among the electoral districts was as follows:[4]
| Province | Arrondissement | Seats |
|---|---|---|
| 8 | ||
| 3 | ||
| 3 | ||
| 2 | ||
| 1 | ||
| 2 | ||
| 4 | ||
| 3 | ||
| 8 | ||
| 1 | ||
| 3 | ||
| 3 | ||
| 3 | ||
| 2 | ||
| 2 | ||
| 4 | ||
| 3 | ||
| 1 | ||
| 1 | ||
| 1 | ||
| 5 | ||
| 16 | ||
| 4 | ||
| 4 | ||
| 2 | ||
| 7 | ||
| 3 | ||
| 6 | ||
| 3 | ||
| 2 | ||
| 2 | ||
| 9 | ||
| 4 | ||
| 1 | ||
| 1 | ||
| 1 | ||
| 1 | ||
| 1 | ||
| 4 | ||
| 2 | ||
| 2 |