1888 United States presidential election in Louisiana explained

See main article: 1888 United States presidential election.

Election Name:1888 United States presidential election in Louisiana
Country:Louisiana
Flag Year:1861b
Type:presidential
Ongoing:no
Previous Election:1884 United States presidential election in Louisiana
Previous Year:1884
Next Election:1892 United States presidential election in Louisiana
Next Year:1892
Election Date:November 6, 1888
Image1:StephenGroverCleveland.png
Nominee1:Grover Cleveland
Party1:Democratic Party (United States)
Home State1:New York
Running Mate1:Allen G. Thurman
Electoral Vote1:8
Popular Vote1:85,032
Percentage1:73.37%
Nominee2:Benjamin Harrison
Party2:Republican Party (United States)
Home State2:Indiana
Running Mate2:Levi P. Morton
Electoral Vote2:0
Popular Vote2:30,660
Percentage2:26.46%
Map Size:350px
President
Before Election:Grover Cleveland
Before Party:Democratic Party (United States)
After Election:Benjamin Harrison
After Party:Republican Party (United States)

The 1888 United States presidential election in Louisiana took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.

Louisiana voted for the Democratic nominee, incumbent President Grover Cleveland, over the Republican nominee, Benjamin Harrison. Cleveland won the state by a large margin of 46.91%.

See also