1888 United States presidential election in Florida explained

See main article: 1888 United States presidential election.

Election Name:1888 United States presidential election in Florida
Country:Florida
Flag Year:1868
Type:presidential
Ongoing:no
Previous Election:1884 United States presidential election in Florida
Previous Year:1884
Next Election:1892 United States presidential election in Florida
Next Year:1892
Election Date:November 6, 1888
Image1:StephenGroverCleveland.png
Nominee1:Grover Cleveland
Party1:Democratic Party (United States)
Home State1:New York
Running Mate1:Allen G. Thurman
Electoral Vote1:4
Popular Vote1:39,557
Percentage1:59.48%
Nominee2:Benjamin Harrison
Party2:Republican Party (United States)
Home State2:Indiana
Running Mate2:Levi P. Morton
Electoral Vote2:0
Popular Vote2:26,529
Percentage2:39.89%
Map Size:400px
President
Before Election:Grover Cleveland
Before Party:Democratic Party (United States)
After Election:Benjamin Harrison
After Party:Republican Party (United States)

The 1888 United States presidential election in Florida took place on November 6, 1888. All contemporary 38 states were part of the 1888 United States presidential election. Florida voters chose four electors to the Electoral College, which selected the president and vice president.

Florida was won by the Democratic nominees, incumbent President Grover Cleveland of New York and his running mate Allen G. Thurman of Ohio.

This was the last election until 2020 that Florida increased its margin to an incumbent who lost re-election nationally.

Results

United States presidential election in Florida, 1888[1]
PartyCandidateVotesPercentageElectoral votes
DemocraticGrover Cleveland (incumbent)39,55759.48%4
RepublicanBenjamin Harrison26,52939.89%0
ProhibitionClinton Fisk4140.62%0
Totals66,500100.00%4
Voter turnout

Notes and References

  1. Dave Leip's U.S. Election Atlas; Presidential General Election Results – Florida