1888 United States presidential election in Connecticut explained

See main article: 1888 United States presidential election.

Election Name:1888 United States presidential election in Connecticut
Country:Connecticut
Type:presidential
Ongoing:no
Previous Election:1884 United States presidential election in Connecticut
Previous Year:1884
Next Election:1892 United States presidential election in Connecticut
Next Year:1892
Election Date:November 6, 1888
Image1:StephenGroverCleveland.png
Nominee1:Grover Cleveland
Party1:Democratic Party (United States)
Home State1:New York
Running Mate1:Allen G. Thurman
Electoral Vote1:6
Popular Vote1:74,920
Percentage1:48.66%
Nominee2:Benjamin Harrison
Party2:Republican Party (United States)
Home State2:Indiana
Running Mate2:Levi P. Morton
Electoral Vote2:0
Popular Vote2:74,584
Percentage2:48.44%
Map Size:250px
President
Before Election:Grover Cleveland
Before Party:Democratic Party (United States)
After Election:Benjamin Harrison
After Party:Republican Party (United States)

The 1888 United States presidential election in Connecticut took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.

Connecticut voted for the Democratic nominee, incumbent President Grover Cleveland over the Republican nominee Benjamin Harrison. Cleveland won the state by a very narrow margin of 0.22%; it was the only New England state that he carried in the election.

This was the first time Darien voted for a Democratic Presidential candidate, and would be the last time until 2016 when Hillary Clinton won it by eleven points over Republican Donald Trump.

See also