1886 Rhode Island gubernatorial election explained

Election Name:1886 Rhode Island gubernatorial election
Country:Rhode Island
Flag Year:1882
Type:Presidential
Ongoing:no
Previous Election:1885 Rhode Island gubernatorial election
Previous Year:1885
Next Election:1887 Rhode Island gubernatorial election
Next Year:1887
Election Date:April 7, 1886
Nominee1:George P. Wetmore
Party1:Republican Party (United States)
Popular Vote1:14,340
Percentage1:53.36%
Nominee2:Amasa Sprague
Party2:Democratic Party (United States)
Popular Vote2:9,944
Percentage2:37.00%
Nominee3:George H. Slade
Party3:Prohibition Party
Popular Vote3:2,585
Percentage3:9.62%
Governor
Before Election:George P. Wetmore
Before Party:Republican Party (United States)
After Election:George P. Wetmore
After Party:Republican Party (United States)

The 1886 Rhode Island gubernatorial election was held on April 7, 1886. Incumbent Republican George P. Wetmore defeated Democratic nominee Amasa Sprague with 53.36% of the vote.

General election

Candidates

Major party candidates

Other candidates