| Election Name: | 1886 Georgia gubernatorial election |
| Country: | Georgia (U.S. state) |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1884 Georgia gubernatorial election |
| Previous Year: | 1884 |
| Next Election: | 1888 Georgia gubernatorial election |
| Next Year: | 1888 |
| Election Date: | 6 October 1886 |
| Nominee1: | John B. Gordon |
| Party1: | Democratic Party (United States) |
| Popular Vote1: | 101,159 |
| Percentage1: | 99.20% |
| Governor | |
| Before Election: | Henry Dickerson McDaniel |
| Before Party: | Democratic Party (United States) |
| After Election: | John B. Gordon |
| After Party: | Democratic Party (United States) |
The 1886 Georgia gubernatorial election was held on 6 October 1886 in order to elect the Governor of Georgia. Democratic nominee, former United States Senator from Georgia and candidate for Governor in the 1868 election John B. Gordon ran unopposed and thus won the election.[1]
On election day, 6 October 1886, Democratic nominee John B. Gordon won the election with 99.20% of the vote, thereby holding Democratic control over the office of Governor. Gordon was sworn in as the 53rd Governor of Georgia on 9 November 1886.[2]